plz ans this fast n correctly
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Let the first term of AP be 'a' and the common difference be 'd'.
So,
- m'th term = a+(m-1)d
- n'th term = a+(n-1)d
- (m+n)th term = a+(m+n-1)d = x
Given :-
m x (m'th term) = n x (n'th term)
ma + dm(m-1) = na + dn(n-1)
ma-na+dm²-dm -dn² +dn = 0
a(m-n) +d(m²-n²)-d(m-n) = 0
a(m-n) +d(m-n) (m+n-1) =0
(m-n) [ a+d(m+n-1) ] = 0
[ a+d(m+n-1) ] = 0
Hence , x = 0
And therefore, = 1
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