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if x+1/x=4 find x^3-1/x^3
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since
x+1/x =4,
then
(x+1/x)²=4²,
x²+1/x² + 2 = 16
then
x²+1/x²=16-2=14,
hence
(x-1/x)²=x²+1/x²-2,
(x-1/x)²=14-2=12,
(x-1/x) = √12=2√3,
therefore
x³-1/x³,
(x-1/x) (x²+1/x²+1),
2√3 × (14+1),
30√3
x+1/x =4,
then
(x+1/x)²=4²,
x²+1/x² + 2 = 16
then
x²+1/x²=16-2=14,
hence
(x-1/x)²=x²+1/x²-2,
(x-1/x)²=14-2=12,
(x-1/x) = √12=2√3,
therefore
x³-1/x³,
(x-1/x) (x²+1/x²+1),
2√3 × (14+1),
30√3
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