plz ans this physics question wid proper explanation
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acceleration = (v-u)/t
t=4 second
v =-2 and u=10
a = (-2-10)/4
a=-3m/s^2
thanks
UDIT (^^♪
t=4 second
v =-2 and u=10
a = (-2-10)/4
a=-3m/s^2
thanks
UDIT (^^♪
patilp:
ty
Answered by
34
Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝
Question:-
an object with a mass of 10kg moves at a constant velocity of 10m/s. A constant force then acts for 4 sec on the object and gives it a speed of 2m/sec in opposite direction. The acceleration produced in it is,
Answer:-)initial velocity(u)= 10m/s
Final velocity(v)= -2m/s
Force=m(v-u)/t= 10(-2-10)/4= -30N
force=m*a
a=f/m= -30/10= -3m/$²
Question:-
an object with a mass of 10kg moves at a constant velocity of 10m/s. A constant force then acts for 4 sec on the object and gives it a speed of 2m/sec in opposite direction. The acceleration produced in it is,
Answer:-)initial velocity(u)= 10m/s
Final velocity(v)= -2m/s
Force=m(v-u)/t= 10(-2-10)/4= -30N
force=m*a
a=f/m= -30/10= -3m/$²
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