Math, asked by umiko28, 1 year ago

plz ans this question

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Answered by Anonymous

0

Answer:

molecular mass of BaSO4=233.27g/mol

233.27g of BaSO4 contains 32g of sulphur

.668g of BaSO4 contains -.668×32×1/233.27

=.094g (approx)

percentage of sulphur in the given compound=.094/.468 ×1/100

=2percent

hope it helps you dude

Answered by Anonymous

7

$Mark \: as \: brainliest$

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