Question

plz ans this question​

Answer 1

Given :

• Initial Velocity, u = 0 m/s

• Final Velocity, v = 144 km/hr

• Time, t = 20 seconds

To Find :

• The distance covered, s

Solution :

First of all convert the final Velocity into it's standard form

$\sf \rightarrow \: 144 \times \dfrac{5}{18}$

$\sf \rightarrow \cancel\dfrac{720}{18} = 40 \: {ms}^{ - 1}$

We'll have to find the acceleration now

From 1st equation of motion :

★ v = u + at

→ 40 = 0 + (a)(20)

→ 40 = 0 + 20a

→ 40 = 20a

→ a = 2 m/s²

Now, using 3rd equation of motion :

★ v² = u² + 2as

→ (40)² = (0)² + 2(2)(s)

→ 1600 = 0 + 4s

→ 4s = 1600

→ s = $\sf\dfrac{1600}{4}$

→ s = 400 m

$\therefore$ The distance covered is 400 m.