Question

plz ans this question ​

Answer 1

Given:

An infinite charged sheet.

To find:

Graph of Field intensity at O ?

Calculation:

First of all, let's find out the field intensity using GAUSS' LAW:

• Consider a cylindrical Gaussian surface opening up on either side of the plane sheet.

$\displaystyle\oint \: \vec{E}. \vec{ds} = \dfrac{q_{enclosed} }{2 \epsilon_{0} }$

$\implies \displaystyle\: 2 \times E \times ds = \dfrac{ \sigma \times ds }{ \epsilon_{0} }$

$\implies \displaystyle\: 2 \times E = \dfrac{ \sigma }{ \epsilon_{0} }$

$\implies E = \dfrac{ \sigma }{2 \epsilon_{0} }$

• So, field intensity is independent of distance and remains constant.

Hence, the graph will be a straight line parallel to Distance Axis. Option c) is correct ✔️