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In triangle ABC right angled at B and from A to C angle of elevation is theta from A to D angle of elevation is 90 - theta.Distance from B to C is 4m and from B to D is 9 m.AB is height
BD =BC + CD
9 = 4 + CD
CD = 5m
Tan theta = AB ÷BC
= AB ÷ 4
Tan 90 - theta = AB ÷ BD
= AB ÷ 9
Tan 90 - theta = cot theta
tan theta × cot theta= 1
AB ÷ 4 × AB ÷ 9 = 1
AB × AB ÷ 36 =1
AB square = 36
AB = 6
Therefore,height of the tower is 6m
lavish48:
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