Math, asked by Avni06, 10 months ago

plz ans this question ASAP step by step ​

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Answered by AkshatZayn
3

\rm \frac{1}{\sqrt{3} + \sqrt{2}}

Rationalising the numerator & denominator:

= \rm \frac{1}{\sqrt{3} + \sqrt{2}} × \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}}

= \rm \frac{\sqrt{3} - \sqrt{2}}{\sqrt{3}^2 - \sqrt{2}^2 }

= \rm \frac{\sqrt{3} - \sqrt{2}}{3 - 2 }

= \rm \frac{\sqrt{3} - \sqrt{2}}{1 }

= \rm \sqrt{3} - \sqrt{2}

Answered by Anonymous
4

Answer:

hey mate....here is your answer...

Option C is correct

hope it helps ❤️✌️

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