Question

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Answer 1

Answer:

P is the centre and AB is the diameter of circle.

e.g., A-------------P------------B

here , AP = PB = radius of circle.

It means, P divides the line segment AB in 1 : 1 ratio.

Using midpoint section formula,

I mean, if two points (x₁,y₁) , (x₂,y2) are given then, midpoint of line joining the given points is {(x₁ + x₂)/2 , (y₁ + y₂)/2}

Let B = (x, y) , A = (2, -3)

so, P ≡ (-2,0) ≡ {(-2 + x)/2, (0 + y//2 }

(-2,0) = {(-2 + x)/2 , y/2 }

-2 = (2 + x)/2

⇒-4 = 2 + x

⇒x = -6

0 = (y - 3)/2

⇒0 = y - 3

⇒y = 3

Therefore the coordinates of point B is (-6,3).

Answer 2

Step-by-step explanation:

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