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Prove the following..
Trigonometric identities..
Its urgent
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Answered by
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Step-by-step explanation:
=sin A/ 1 - cos A
=sin A(1+cos A) / 1-cos²A
=sin A(1+cosA) / sin² A
=(1+cos A ) / sin A
=cosec A + cot A.
Answered by
1
Answer:
sinA/1-cosA,
Multiply numerator and denominator by (1+cosA),
LHS=sinA(1+cosA) /(1-cosA) (1+cosA)
=sinA(1+cosA)/(1-cos^2A)
=sinA(1+cosA)/sin^2A [Since,sin^2A+cos^2A=1]
=(1+cosA)/sinA
=1/sinA+cosA/sinA
=cosecA+cotA=RHS
Therefore,LHS=RHS
Hence Proved.
Hope it helps you.
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