plz ans this :) with steps please
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class102:
hey bro r u solving it in a paper
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37.
⇒ 3√5 x² + 25x - 10√5 = 0
⇒ 3√5 x² + 30x - 5x - 10√5 = 0
⇒ 3√5x ( x + 2√5 ) - 5 ( x + 2√5 ) = 0
⇒ ( x + 2√5 ) ( 3√5x - 5 ) = 0
Zeroes are = ( -2√5 ) and ( 5/3√5 ).
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38.
⇒ √3x² - 2√2x - 2√3 = 0
⇒ √3x² - 3√2x + √2x - 2√3 = 0
⇒ √3x ( x - √6 ) + √2 ( x - √6 ) = 0
⇒ ( x - √6 ) ( √3x + √2 ) = 0
Zeroes = √6 and ( -√2/√3 ).
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39.
⇒ 4√3x² + 5x - 2√3 = 0
⇒ 4√3x² + 8x - 3x - 2√3 = 0
⇒ 4x ( √3x + 2 ) - √3 ( √3x + 2 ) = 0
⇒ ( √3x + 2 ) ( 4x - √3 ) = 0
Zeroes = ( -2/√3 ) and ( √3/4 ).
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40.
⇒ √2x² - 3x - 2√2 = 0
⇒ √2x² - 4x + x - 2√2 = 0
⇒ √2x ( x - 2√2 ) + 1 ( x - 2√2 ) = 0
⇒ ( x - 2√2 ) ( √2x + 1 ) = 0
Zeroes = ( 2√2 ) and ( -1/2√2 ).
Hope it helps !
37.
⇒ 3√5 x² + 25x - 10√5 = 0
⇒ 3√5 x² + 30x - 5x - 10√5 = 0
⇒ 3√5x ( x + 2√5 ) - 5 ( x + 2√5 ) = 0
⇒ ( x + 2√5 ) ( 3√5x - 5 ) = 0
Zeroes are = ( -2√5 ) and ( 5/3√5 ).
==============================
38.
⇒ √3x² - 2√2x - 2√3 = 0
⇒ √3x² - 3√2x + √2x - 2√3 = 0
⇒ √3x ( x - √6 ) + √2 ( x - √6 ) = 0
⇒ ( x - √6 ) ( √3x + √2 ) = 0
Zeroes = √6 and ( -√2/√3 ).
================================
39.
⇒ 4√3x² + 5x - 2√3 = 0
⇒ 4√3x² + 8x - 3x - 2√3 = 0
⇒ 4x ( √3x + 2 ) - √3 ( √3x + 2 ) = 0
⇒ ( √3x + 2 ) ( 4x - √3 ) = 0
Zeroes = ( -2/√3 ) and ( √3/4 ).
=============================
40.
⇒ √2x² - 3x - 2√2 = 0
⇒ √2x² - 4x + x - 2√2 = 0
⇒ √2x ( x - 2√2 ) + 1 ( x - 2√2 ) = 0
⇒ ( x - 2√2 ) ( √2x + 1 ) = 0
Zeroes = ( 2√2 ) and ( -1/2√2 ).
Hope it helps !
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Your answer is on the pic.
Hope it helps.
Hope it helps.
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