plz ans to be brainlist
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gaurav2013c:
what to find
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Answered by
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Since x-a is a factor of given polynomial,
a is zero of given polynomial.
By Remainder theoram,
P(a) = 0
=> (a) ^3 - a(a)^2 +(6-a) = 0
=> a^3 - a^3 +6 - a = 0
=> 6 - a = 0
=> a = 6
a is zero of given polynomial.
By Remainder theoram,
P(a) = 0
=> (a) ^3 - a(a)^2 +(6-a) = 0
=> a^3 - a^3 +6 - a = 0
=> 6 - a = 0
=> a = 6
There is nothing to find in Remainder
No remainder will not 0
Take a Example,,, we know that 5 is a factor of 25, So If we divide 25 by 5, the Remainder will be 0
same is with this question
I think that we have to find the value of a
but I don't think
ok.... do whatever you want.....
ok
Cool bro, I think we have to find the value of a @Vaishnavi.
ok
Answered by
1
Given f(x) = x^3 - ax^2 + (6 - a).
if x - a = 0, then x = a.
To know the remainder when f(x) is divided by x - a.
Plug in x = a in f(x), we get
f(a) = a^3 - a(a)^2 + (6 - a)
= a^3 - a*a^2 + 6 - a
= a^3 - a^3 + 6 - a
= 6 - a.
Hope this helps!
if x - a = 0, then x = a.
To know the remainder when f(x) is divided by x - a.
Plug in x = a in f(x), we get
f(a) = a^3 - a(a)^2 + (6 - a)
= a^3 - a*a^2 + 6 - a
= a^3 - a^3 + 6 - a
= 6 - a.
Hope this helps!
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