Question

plz Ans with explanation in notebook and in graph​

Answer 1

Answer :

Given equations :

• X = 2
• X = 4
• Y = 1
• Y - 3 = 0 => Y = 3

Note :

• The graph of line X = k is parallel to y-axis and passes through the point X = k
• The graph of line Y = k is parallel to x-axis and passes through the point Y = k

Keeping the points mentioned in note in mind , I've sketched the graph

Finding area bounded by lines :

• After sketching the graph , find out the points of intersection using the graph , The points that we get are A(2,1) B(4,1) C(2,3) D(4,3)
• Find out the distance between the points

Distance between points (a,b) and (c,d) is

Distance = √(a-c)² + (b-d)²

Distance between AB = √(4-2)² + (1-1)²

Distance between AB = √(2)²

Distance between AB = 2 units

Distance between BC = √(4-4)² + (3-1)²

Distance between BC = √2²

Distance between BC = 2 units

Distance between CD = √(4-2)² + (3-3)²

Distance between CD = √2²

Distance between CD = 2 units

Distance between DA = √(2-2)² + (3-1)²

Distance between DA = √2²

Distance between DA = 2 units

Here we got all sides equal , hence it could be a square or rhombus , to confirm if it is a square or rhombus , let's check the diagonal lengths

Let diagonals be AC and BD

Distance between AC = √(4-2)²+(3-1)²

Distance between AC = √2²+2²

Distance between AC = 2√2 units

Distance between BD = √(2-4)²+(3-1)²

Distance between BD = √2²+2²

Distance between BD = 2√2 units

Here , we got diagonal lengths equal , hence the figure is a square

• Area of a square = (side length)²
• Area of square = (2)²
• Area of square = 4 sq.units

Hence, area bounded by the graph is 4sq.units