Question

Plz ans with step by step explanation. ​

Answer 1

$\huge\bold\red{a)}$



Plz mark as brainlist....

Answer 2

${(x + y)}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2}$

given

$(x + \frac{1}{x} ) = a \\ \\ cubing \: on \: both \: sides \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3 {x}^{2} \frac{1}{x} + 3x \frac{1}{ {x}^{2} } = {a}^{3} \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3(x + \frac{1}{x} ) = {a}^{3} \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } = {a}^{3} - 3(x + \frac{1}{x} ) \\ \\ {x}^{3} + \frac{1}{ {x}^{3} } = {a}^{3} - 3a$

hope it helps