plz anser it fast .. with solution
Attachments:

Answers
Answered by
1
Heya
We know, for a 2x2 matrix with labels a,b,c,d :

Hence, we calculate the determinant as :


Since the two angles is complimentary, sum of angles is 90°
Hence, the Value :

Thus, we conclude that only (2) is correct.
We know, for a 2x2 matrix with labels a,b,c,d :
Hence, we calculate the determinant as :
Since the two angles is complimentary, sum of angles is 90°
Hence, the Value :
Thus, we conclude that only (2) is correct.
Anonymous:
=_=
Similar questions