Question

plz answ
er this question ​

Answer 1

√5/2-√5

rationalise the denominator

√5/2-√5 × 2+√5/2+√5

2√5 + 5/4-5

2√5 + 5/-1

5-2√5

Answer 2

Step-by-step explanation:

$\frac{ \sqrt{5} }{ 2 - \sqrt{5} }$

$\frac{ \sqrt{5} }{ 2 - \sqrt{5} } =\frac{2 + \sqrt{5} }{ 2 + \sqrt{5} }$

$\frac{ \sqrt{5}(2 + \sqrt{5}) }{(2 - \sqrt{5})(2 + \sqrt{5}) }$

$\frac{2 \sqrt{5} + 5 }{4 - 5}$

tex] \frac{2 \sqrt{5} + 5 }{-1} [/tex]