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May this will help you
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<BEC + <DEC = 180°
<DEC = 180 - <BEC = 180 - 130 = 50°
in ∆CDE:
<ECD + <EDC + <DEC = 180°
<EDC = 180° - 50° - 20° = 110°
<BAC = <EDC ___ angles in same chord are equal
therefore <BAC = 110°
<DEC = 180 - <BEC = 180 - 130 = 50°
in ∆CDE:
<ECD + <EDC + <DEC = 180°
<EDC = 180° - 50° - 20° = 110°
<BAC = <EDC ___ angles in same chord are equal
therefore <BAC = 110°
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