Math, asked by aadi2203, 1 year ago

plz answer..............?

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Answered by praneethks
0
It is given (2a-3b)=3 and ab=2 .
{(x - y)}^{3} =  {x}^{3}  -  {y}^{3}  - 3xy(x - y)
So
{(2a - b)}^{3} ={ 3}^{3}   = 27
=>
  {(2a)}^{3} -  {(3b)}^{3}  - 3(2a)(3b)(2a - 3b)= 27
=>
8 {a}^{3}  - 27 {b}^{3}  - 6ab(2a - 3b) = 27
=>
8 {a}^{3}  - 27 {b}^{3}  - 6(2)(3) = 27
=>
8 {a}^{3}  - 27 {b}^{3}  = 27 + 36 = 63.
Value of the required value=63. Hope it helps you...
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