Question

plz answer 5 question​ ans fast

Answer 1

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Given:

(i) Taking A as origin ,

We will take AD as x-axis and AB y- axis

and coordinate of point P,Q and R are (4,6),(3,2)&(6,5) respectively.

Area of triangle PQR

=1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

=1/2[4(2-5)+3(5-6)+6(6-2)]

=1/2[-12-3+24]

=9/2 square units.

As this, in (ii)

Taking C as origin CB as x-axis and CD as y- axis.

Coordinate of P ,Q and R are (12,2),(13,6),&(10,3)

Area of ∆ PQR

= 1/2[12(6-3)+13(3-2)+10(2-6)]

=1/2[36+13-40]

=9/2 square units.

It can be observed that the area of the triangle is same in both the cases

Hope it helps you ❣️☑️☑️