Question

Plz answer 8 question

Answer 1

sample SPACE={HHH,HHT,HTH,THH,TTH,TTT}
I HAVE retern sample wsing this sample sapce you can eassyly find ans of this qusetionsi,ii,iii

Answer 2

Given that total number of coins tossed = 3.

(1) The total number of possible outcomes:

S = {HHH,HHT,HTH,THH,HTT,THT,TTH,TTT} 

n(S) = 8.


(2) The probability of 3 heads coming up:

Let E be the event of getting 3 heads.

E = {HHH}.

n(E) = 1.

Therefore P(E) = n(E)/n(S)

                         = 1/8.



(3) The probability of getting at least one head

Let E be the event of getting at least one head.

E = {HTT,THT,TTH,HHT,HTH,THH,HHH}

n(E) = 7.

P(E) = 7/8.



(4) Probability of getting more tails than heads


Let E be the event of getting more tails than heads.

E = {HTT,TTH,TTT,THT}.

n(E) = 4.

P(E) = n(E)/n(S)

       = 4/8

       = 1/2.


Hope this helps!