Plz answer a simple que of trignometry
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Hii There!!!
tan3x = sin45°cos45° + sin30°
On putting respective values we get,
= (1/√2)×(1/√2) + 1/2
= 1/2 + 1/2
= 1
tan 45° = 1
=> tan3x = 45
=> x = 15°
===================
Hope it helps
tan3x = sin45°cos45° + sin30°
On putting respective values we get,
= (1/√2)×(1/√2) + 1/2
= 1/2 + 1/2
= 1
tan 45° = 1
=> tan3x = 45
=> x = 15°
===================
Hope it helps
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