Question

plz answer all questions fast

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Answer 1

Answer:

Q1.

Match

a) - 2)

b) - 4)

c) - 1)

d) - 5)

e) - 3)

Q2.

HCF 15,45 and 95

15 = 3×5

45 = 3×3×5

95 = 5×19

5 is common in 15,45 and 95

Therefore,

HCF of 15,45 and 95=5 :Ans

Q3.

The no. is divisible by 5 and 12. Since 5 and 12 are co-prime nos. so the no. must be divisible by the product 5×12=60. so, the given no. will always be divisible by 60. :Ans

Q4.

first write from above picture

Therefore,

Prime factorization of 480=2×2×2×2×2×3×5:Ans

Q5.

HCF 398,468 and 702

398 = 2×199

468 = 2×2×3×3×13

702 = 2×3×3×3×13

2 is common in 398,468 and 702

Therefore,

HCF of 398,468 and 702 = 2 :Ans

Q6.

HCF 18,27,36 and 63

18 = 2×3×3

27 = 3×3×3

36 = 2×2×3×3

63 = 3×3×7

3 is common in 18,27,36 and 63

Therefore,

HCF of 18,27,36 and 63 = 3 :Ans

Q7.

First we have to find LCM of 4,7,12 and 84

4 = 2×2

7 = 7

12 = 2×2×3

84 = 2×2×3×7

LCM OF 4,7,12 and 84= 2×2×3×7= 84

84sec = 1min 24sec

Therefore,

The bells will again ring together 84sec after

6a.m. : Ans

Q8.

To find ans. we have to find HCF of 825,675 and 450

825=3×5×5×11

675=3×3×3×5×5

450=2×3×3×5×5

HCF of 825,675 and 450= 3×5×5=75

Therefore,

75 cm is the longest tape which can measure the three dimensions of the room :Ans

Q9.

let a and b the two nos.

LCM(a,b) × HCF(a,b) = product of two nos.

108×HCF = 972

HCF= 972/108

HCF= 9 :Ans

Q10.

Let a and b the two nos.

and a=75

LCM(a,b) × HCF(a,b) = a×b

525×25=75×b

13125=75b

13125/75=b

175=b :Ans

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