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given, ABCD is a rectangle.
so, x+59°=90
x=90°-59
x=31°
angle OAB= angle BAD=31°
[vertically opposite angles]
angle ODC= angle BDA=59°
[vertically opposite angles]
angle ACB= angle ABD
[vertically opposite angles]
angle OAC=DBO=59°.
[vertically opposite angles]
y= 59°
AOC+OCA+CAO= 180°
AOC+59°+59°=180°
AOC=180°-118°
AOC=62°
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