Question

PLZ ANSWER AND ENJOY YOUR PTS Q:Find the value of k for which the roots of the equation kx(3x-2)+4=0, are equal. Also find the roots of the equation, so formed, using quadratic formula.

Answer 1

Step-by-step explanation:

The value of x=1/3

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Answer 2

Step-by-step explanation:

kx(3x-2)+4=0

3kx²-2kx+4=0

If the roots are equal then, b²-4ac=0

In the given equation,

a=3k,b=2k, c=4.

(2k)²-4(3k)(4)=0

4k²-48k=0

4k²=48k

k=48k/4k

k=12.

a=3(12)=36.

b=2(12)=24.

Now the equation is:

36x²-24x+4=0

b²-4ac=(24)²-4(36)4

=576-576=0

x=-b+/-√b²-4ac/2a

x=-(-24)+0/2(36)=24/72=1/3.

x=-(-24)-0/2(36)=24/72=1/3.

Therefore, 1/3 and 1/3 are roots of the equation.

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