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answer-4,chapter -kinematics
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time of flight for two complementary angles .
theta and ,(90- theta)
⏩in this case range is same for angles of projection theta and (90-theta )
but has different time if flight .
✨time if flight
T = (2usintheta )/g
T '= [2u sin(90-theta )]/g
then,
T/T'= tan theta
and ,
T T' = 2R/g
then ,
R= T T' g/2
⏩so correct Answer is 4)
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solution ;
time of flight for two complementary angles .
⏩
time of flight
T = (2usintheta )/g
T '= [2u sin(90-theta )]/g
then,
T/T'= tan theta
T T' = 2R/g
then ,
R= T T' g/2
correct
Answer is 4)
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