Question

plz answer anybody want 50 points,,, don't say that l don't no answer,, if you don't no don't answer..​

Answer 1

Answer:

for 1

..x and y are 45 degrees

for 2

..x and y are 50 degrees

for 3

..x is 28

y is 62

Answer 2

Answer:

(i) ABCD is a rhombus.

We know that rhombus is type of parallelogram whose all sides are equal.

In ∆ABC, ∠​BAC = ∠BCA = (180° − 110°) = 35°

Hence x = 35°

But AB || DC …opposite sides of rhombus are parallel

∠​BAC = ∠DCA …for transversal AC

∴ ∠​BAC = ∠DCA = 35°

Hence, x = y = 35°

(ii) ABCD is a rhombus.

We know that the diagonals of a rhombus are perpendicular bisectors of each other.

∴ in ∆​AOB, ​

∠OAB = 40°, ∠AOB = 90°

∴ ∠ABO = 180° − (40° + 90°) = 50°

Hence x = 50°

Now in ∆DAB,

AB = AD … as rhombus has all sides equal.

ie. ∆​AOB is isosceles triangle.

Also base angles of isosceles triangle are equal.

Hence, x = y = 50°

(iii) ABCD is a rhombus.

We know that rhombus is type of parallelogram whose all sides are equal.

So in ∆DCB,

DC = BC

∴ ∠​CDB = ∠CBD = y° base angles of isosceles triangle are equal.

Now, x = ∠​CAB …alternate angles with transversal AC

∴ x = ∠​BAD

∴ x = × 62°

∴ x = 31°

In ∆DOC,

We know sum of angles of triangle is 180°

∠CDO + ∠DOC + ∠OCD = 180°

∴ ∠CDO + 90° + 31° = 180°

∴ ∠CDO = 59°

∴ y = 59°

Hence, x = 31° and y = 59°

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