Physics, asked by kannubajaj, 1 year ago

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Answered by Anonymous
10
i) The glow of the bulbs B2 and B3 will remain the same
) When the bulbs are in parallel, wattage will be added (4.5 W) and the ammeter reading would be 

4.5/4.5=1

(iii) Since ammeter reading is 1 ampere , resistance of the combination is = 4.5/1.0=4.5

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