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a^2 + b^2 + c^2- ab - bc - ca
=1/2(2a^2 + 2b^2 + 2c^2- 2ab - 2bc - 2ca)
=1/2(a^2+ b^2- 2ab+ b^2+ c^2- 2bc+ c^2+ a^2 -2ca)
=1/2(a-b)^2(b-c)^2(c-a)^2
We know that square of any no. is never 0 and can never be negative.
so.. a^2 + b^2 + c^2- ab - bc - ca is always non negative for all values a,b&c.
IF THIS HELPED UH.. PLZZ MARK AS BRAINILIEST.
=1/2(2a^2 + 2b^2 + 2c^2- 2ab - 2bc - 2ca)
=1/2(a^2+ b^2- 2ab+ b^2+ c^2- 2bc+ c^2+ a^2 -2ca)
=1/2(a-b)^2(b-c)^2(c-a)^2
We know that square of any no. is never 0 and can never be negative.
so.. a^2 + b^2 + c^2- ab - bc - ca is always non negative for all values a,b&c.
IF THIS HELPED UH.. PLZZ MARK AS BRAINILIEST.
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