Question

plz answer borahae
chemistry
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Answer 1

$⇒\:Fe \:+\:CuS{O}_{4} \:⟶\: FeS{O}_{4} \:+\: Cu$

$⇒\:Mg\:+\:2HCL\:⟶\:MgC{L}_{2}\:+{H}_{2}$

$⇒\:ZnS{O}_{4}\:+\:Cu\:⟶\: Ø\: no \: reaction$

$⇒\:2Cu\:+\:{H}_{2}O \:+\:C{O}_{2}\:+\:{O}_{2}\:⟶\:Cu{(OH)}_{2}\:+\:CuC{O}_{3}$