plz answer both 6 and 7
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hello here is your answer
Q 6.
let the two acute angles be x
therefore 3x and 7x are the two acute angles.
third angle is 90°
so, by the angle sum property of a ∆
3x+7x+90=180
10x=90
so, x= 90/10= 9
therefore the two acute angles are
3(9) =27° and 7(9) 63°
Q. 7 one of the angle is 65° and let other two angles be
2x and 3x
therefore again by angle sum property of the∆
2x+3x+65°=180°
5x=180-65
5x=115°
so x= 23°
therefore the angles are
23(2) = 46° and 23(3) = 69°
HOPE IT HELPS!!
Q 6.
let the two acute angles be x
therefore 3x and 7x are the two acute angles.
third angle is 90°
so, by the angle sum property of a ∆
3x+7x+90=180
10x=90
so, x= 90/10= 9
therefore the two acute angles are
3(9) =27° and 7(9) 63°
Q. 7 one of the angle is 65° and let other two angles be
2x and 3x
therefore again by angle sum property of the∆
2x+3x+65°=180°
5x=180-65
5x=115°
so x= 23°
therefore the angles are
23(2) = 46° and 23(3) = 69°
HOPE IT HELPS!!
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