Question

plz answer both the questions​

Answer 1

Answer:

3. NaCl < LiCl < BeCl2

Explanation:

In a bond between two atoms M and X, the amount of covalent character in the M-X bond will depend on the difference in electronegativity ΔEN be the two atoms.

If ΔEN is small, the bond will have a large amount of covalent character.

If ΔEN is large, the bond will have a small amount of covalent character.

The electronegativity of atoms increases from top to bottom and from left to right in the Periodic Table.

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Cl is on the top right of the Periodic Table, while Li, Be, and Na are clustered on the top left.

But Na is closest to the bottom and Be is closest to the right.

Electronegativities increase in the order Na < Li < Be, so

ΔEN decreases in the order  Na-Cl > Li-Cl > Be-Cl.

∴ The degree of covalent character increases in the order

NaCl < LiCl < BeCl2

Answer 2

here is your answer for b question while going down in a group in peroidic table it covalant nature increases so licl is less than nacl less than kcl less than rbcl less than cscl answer for c question

hybridisation of clo3- is sp3

hybridisation of br3- don't know

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