plz answer both these questions
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Answer:
1)a = 6+2√3
1/a = 1/6+2√3
→ = 1/6+2√3 × 6-2√3/6-2√3
→ = (6-2√3)/(6+2√3)(6-2√3)
→ = (6-2√3)/(6²-(2√3)²)
→ = (6-2√3)/(36-4(3))
→ = (6-2√3)/(36-12)
→ = (6-2√3)/24
★a-1/a
→ 6+2√3 - (6-2√3)/24
→ {24(6+2√3) - 6 + 2√3}/24
→ {144+48√3-6+2√3}/24
→ {138+50√3}/24
→ 138/24 + 50√3/24
→ 23/4 + 25√3/12
→ {69+25√3}/12
→ {69+√1875}/12
→ 3{23+√625}/12
→ {23+25}/4
= 48/4
=12
2)
x = 7 + √40
=5 + 2 + 2√10 = (√5 + √2)²
√x = √5 + √2
1/√x = 1/(√5 + √2) = (√5 - √2)/((√5 + √2)(√5 - √2) = (√5 - √2)/(5 - 2) = (√5 - √2)/3
√x + 1/√x = √5 + √2 + (√5 - √2)/3 = (2/3)(2√5 + √2)
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