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Answer:
well done Is batter then well said
∠BCD = 100°.
Step-by-step explanation:
Given information: ∠ABC = 70° and ∠ADB = 30°.
According to the angle sum property, the sum of interior angles of a triangle is 180°.
In triangle ABD,
\angle ABD+\angle BDA+\angle BAD=180^{\circ}∠ABD+∠BDA+∠ BAD=180∘
70^{\circ}+30^{\circ}+\angle BAD=180^{\circ}70∘+30∘+∠ BAD=180∘
100^{\circ}+\angle BAD=180^{\circ}100∘+∠ BAD=180∘
\angle BAD=180^{\circ}-100^{\circ}∠ BAD=180∘−100∘
\angle BAD=80^{\circ}∠ BAD=80∘
In a circle the opposite angles of a cyclic quadrilateral are supplementary.
\angle BAD+\angle BCD=180^{\circ}∠BAD+∠BCD=180∘
80^{\circ}+\angle BCD=180^{\circ}80∘+∠BCD=180∘
\angle BCD=180^{\circ}-80^{\circ}∠BCD=180∘−80∘
\angle BCD=100^{\circ}∠BCD=100∘
Therefore, the measure of angle BCD is 100°.