Question

Plz answer correctly fast

Answer 1

hope this will be usefull

Answer 2

Question:

Solve:

1. $\sf \dfrac{x+3}{2x-5} = \dfrac{3}{2}$

2. $\sf \dfrac{5y-2}{2y+8} = \dfrac{5}{6}$

Solution:

1. $\bf \dfrac{x+3}{2x-5} = \dfrac{3}{2}$

$\implies \sf 2(x+3) = 3(2x-5)$

$\implies \sf 2x+6 = 6x-15$

$\implies \sf 2x-6x = -15-6$

$\implies \sf -4x = -21$

$\implies \sf x = \dfrac{21}{4}$

2. $\bf \dfrac{5y-2}{2y+8} = \dfrac{5}{6}$

$\implies \sf 6(5y-12) = 10yb+ 40$

$\implies \sf 30y - 12 = 10y + 40$

$\implies \sf 30y - 10y = 40 + 12$

$\implies \sf 20y = 52$

$\implies \sf y = \dfrac{13}{5}$