plz answer correctly,I am asking this 7th time,no one answered,plz do help me now. an artificial satellite is revolving in an Orbit close to the surface of earth find the period of revolution of satellite.(g=10m/s)
Answers
Answered by
0
HOPE IT MAY HELP YOU ❤️❤️
Attachments:
Answered by
0
Answer:
84 minutes
Explanation:
Period of a Satellite T=2π√(R+h)³/GM
When a satellite is moving close to the earth,
ie, R+h≅R
∴T=2π√R³/GM
we know g=GM/R²
ie, gR²=GM
∴T=2π√R/g
=2×3.14√6400×1000/10
=6.28×800
=5024 s≈84 minutes
Similar questions
Math,
2 months ago
Math,
5 months ago
Social Sciences,
11 months ago
Computer Science,
11 months ago