Question

plz answer correctly,I am asking this 7th time,no one answered,plz do help me now. an artificial satellite is revolving in an Orbit close to the surface of earth find the period of revolution of satellite.(g=10m/s)​

Answer 1

Answer:

84 minutes

Explanation:

Period of a Satellite T=2π√(R+h)³/GM

When a satellite is moving close to the earth,

                      ie, R+h≅R

∴T=2π√R³/GM

we know g=GM/R²

         ie, gR²=GM

∴T=2π√R/g

   =2×3.14√6400×1000/10

   =6.28×800

   =5024 s≈84 minutes