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divide 6x*6x+13x+5 by2x+1
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good learning in English
I am Rakesh Kumar jammu and kashmir state I'm poor man .
i support BJP PART
please help me
Sir good night
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Given Equation is 6x^2 + 13x + 5.
We need to divide it by 2x+1.
2x+1)6x^2 + 13x + 5(3x + 5
6x^2 + 3x
-----------------------
10x + 5
10x + 5
--------------------------------
0.
Therefore the remainder = 0 and the Quotient = 3x + 5.
Hope this helps!
We need to divide it by 2x+1.
2x+1)6x^2 + 13x + 5(3x + 5
6x^2 + 3x
-----------------------
10x + 5
10x + 5
--------------------------------
0.
Therefore the remainder = 0 and the Quotient = 3x + 5.
Hope this helps!
thanks sir
:-))
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