Question

plz answer
do not spam
answer correctly with explanation ​

Answer 1

OPTION C is the solution.

Answer 2

$\underline{\underline{\mathit{\huge{\purple{ AnSwEr }}}}}$

• $\implies$

$p {x}^{2} + 2q + r = 0$

for real roots

$\implies$

${b}^{2} - 4ac = 0 \\ {2q}^{2} - 4 \times p \times r = 0 \\ 4 {q}^{2} - 4pr = 0$

$\boxed{{q}^{2} = pr}$

• $\implies$

$q {x}^{2} - 2 \sqrt{pr} x + q = 0$

for real roots

${b}^{2} - 4ac = 0 \\ { ( - 2 \sqrt{pr}) }^{2} - 4 \times q \times q = 0 \\ 4pr = 4 {q}^{2}$

$\boxed{{q}^{2} = pr}$

Therefore option (C). is correct

$\mathfrak{\red{\huge{\underline{\overline{ ♡Good }}}}}$ $\mathfrak{\huge{\underline{\overline{\red{ Morning♡ }}}}}$

$<marquee direction = "left" bgcolor = "aqua"> Hope this helps uh☺️❤️✌️$