Math, asked by shatakshi53, 1 year ago

....plz answer (don't worry i hv croped it so much thats why its showing blank ) plz tap the pic ​

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Answered by Anonymous
19
1) \: = > {(25)}^{2} \div {5}^{x + 2} = {(125)}^{3} \\ \\ = > {( {5}^{2} })^{2} \div {5}^{x + 2} = { {(5}^{3} )}^{3} \\ \\ = > {5}^{4} \div {5}^{x + 2} = {5}^{9} \\ \\ = > {5}^{4 - (x + 2)} = {5}^{9} \\ \\ = > {5}^{4 - x - 2} = {5}^{9} \\ \\ = > {5}^{2 - x} = {5}^{9} \\ \\ As \: the \: base \: is \: same \: so \: we \: can \: \\ compare \: the \: power \: and \: find \: \\ the \: value \: of \: x \\ \\ comparing \: the \: powers = > \\ \\ = > 2 - x = 9 \\ \\ = > x = 2 - 9 \\ \\ = > x = - 7 \\ \\ 2) \: = > {7}^{6} \div {(7)}^{4 - x} = {7}^{8} \\ \\ = > {7}^{6- (4 - x)} = \: {7}^{8} \\ \\ = > {7}^{6 - 4 + x} = {7}^{8} \\ \\ = > {7}^{2 + x} = {7}^{8} \\ \\ As \: the \: base \: is \: same \: so \: we \: can \: \\ compare \: the \: power \: and \: find \: \\ the \: value \: of \: x \\ \\ comparing \: the \: powers = > \\ \\ = > 2 + x = 8\\ \\ = > x = 8 - 2 \\ \\ = > x = 6

living36: oh god
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