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Step-by-step explanation:
Pythagoras theorem states that a right angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.
First, we consider the AABD and applying Pythagoras theorem we get,
AB2 = AD2 + BD2
c2h2 + ( a - x)2 h2 = c2 - ( a - x )2 ..(1) First, we consider the AACD and applying Pythagoras theorem we get, AC2 = AD2 + CD² = b2 = h2 + x2
h2 = b2 - x2
From (i) and (ii) we get, c2-(-x)2 = 62 - x2 c2 - a2 - x2 + 2ax = b2 - x2
c2 = a2 + b2 - 2ax =
Hence Proved.
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