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diameter of upper end=40 cm
radius (r₁)=20 cm
diameter of lower end =20 cm
radius(r₂) =10 cm
17.6 l=17.6×1000
=17600 cm³
Volume of a Frustum of a Cone =1÷3×π×h[r₁²+r₂²+r₁r₂]
17600×3=22÷7×h(400+100+200)
17600×3×7÷22=h(700)
800×3×7×1÷100=h
24=h
h=24 cm
l=√h²+(r₁+r₂)²
l=√24²+10²
l=√576+100
l=√676
l=26 cm
area =πl(r₁+r₂)
=22÷7×26(30)
=17160÷7
2451.42 cm²
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