Question

Plz answer fast .A man of mass m is inside a box of same mass .The whole system is suspended with ideal strings and pulley as shown in above figure.The tension t1 in the string so as to keep the system in equilibrium is​

Answer 1

Answer:

hey... mate ur ans... is here

The fixed pulley is taken as frame of reference. the forces on man and box with plank are shown in the figure. The forces are as follows:

i. Weight of the man =mg

ii. The tension in the string =T.

iii. The normal contact force between the man and the plank =N.

iv. The weight of the plank and box =mg

Referring to figure. The equation of motion of the man is given as

T+N−Mg=M a

since $$M > m$$ and the box remains at rest, the man will have to be at rest

T+N−Mg=0 ...(1)

similarly referring to figure,

T−N−mg=ma=0 ...(2)

Solving (1) and (2) we obtain,

T=

2

(m+m)g

and N=

2

(M−m)g

plzz mark as brainlist...XD