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as the given angles are angles of triangle so we apply angle sum property with states that sum of all angles of triangle is 180 degrees
so,
x-40° + x-20°+x/2-10° = 180°
2x + x/2 - 70 = 180°
4x + x /2 = 250°
5x /2 = 180°
5x = 180° * 2
x = 72°
so first angle is.....
x - 40 = 72 - 40 = 32°
second angle is....
x - 20 = 72 - 20 = 52°
thurd angle is.....
x/2 - 10° = 72/2 - 10° =36 - 10 = 26°
so,
x-40° + x-20°+x/2-10° = 180°
2x + x/2 - 70 = 180°
4x + x /2 = 250°
5x /2 = 180°
5x = 180° * 2
x = 72°
so first angle is.....
x - 40 = 72 - 40 = 32°
second angle is....
x - 20 = 72 - 20 = 52°
thurd angle is.....
x/2 - 10° = 72/2 - 10° =36 - 10 = 26°
Answered by
1
Sum of angles of a triangle is 180° the angles are (x-40) , (x-20) and (x/2 - 10).
Sum = (x-40) + (x-20) + (x/2 - 10)
= 180 ⇒ 5x/2 - 70
= 180+70 ⇒ 5x/2
= 250=5x/2
= 250×2=5x
= 500=5x
= x=500/5
= x=100
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Sum = (x-40) + (x-20) + (x/2 - 10)
= 180 ⇒ 5x/2 - 70
= 180+70 ⇒ 5x/2
= 250=5x/2
= 250×2=5x
= 500=5x
= x=500/5
= x=100
if u like my ans plz mark as brainlist and thank and follow me
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