Question

plz answer fast as possible​

Answer 1

Step-by-step explanation:

${ \sin }^{4} x \div 2 + \cos^{2} x \div 3 = \frac{1}{5}$

$\frac{2( \sin(x \cos(x) ^{2} ) }{2} + \frac{ \sin(2)theta \cos(2) theta }{3} = \frac{1}{5}$

$( \sin(x) \cos(x) ) ^{2} + \frac{ \sin(theta) \cos(theta) }{3} = \frac{1}{5}$

$\frac{ \sin ^{8}x }{8} + \frac{ \cos ^{8} x}{27} = \frac{1}{125}$