plz answer fast don't spam plz
Answers
Answer:
Hope u mark me as brainliest
Step-by-step explanation:
perimeter of rectangle=2(l+b)
2(a+5b+7a-b)
2a+10b+14a-2b
p=16a-8b=the area of square
therefore side of square 16a-8b divided by 4
4a+2b=side of square
area of square =4a+2bX4a+2b
(a+b)2=a2+2ab+b2
so area =16a2+16ab+4b2 (1)
area of rctangle =lXb=(a+5b)X(7a-b)
=7a2-ab+35ab-5b2 (2)
(1)-(2)=9a2-18ab+9b2 this much is the area of rectangle less than that of square
0
9a+b
0
Answer:
9a² - 18ab + 9b² square units
Step-by-step explanation:
Length of rectangle = a + 5b units
Breadth of rectangle = 7a - b units
Let the side of square be 'x' units
Perimeter of rectangle = Perimeter of square (Given)
2(l + b) = 4 * side
2(a + 5b + 7a - b) = 4x
2(8a + 4b) = 4x
16a + 8b = 4x
Divide the equation by 4
4a + 2b = x .........(1)
Area of rectangle = l * b
= (a + 5b)(7a - b)
= a(7a - b) + 5b(7a - b)
= 7a² - ab + 35ab - 5b²
= 7a² + 34ab - 5b² square units
Area of square = side * side
= x * x
= (4a + 2b)(4a + 2b)
= 4a(4a + 2b) + 2b(4a + 2b)
= 16a² + 8ab + 8ab + 4b²
= 16a² + 16ab + 4b² square units
Difference between area of square and area of rectangle = ar(square) - ar(rectangle)
= (16a² + 16ab + 4b²) - (7a² + 34ab - 5b²)
= 16a² +16ab + 4b² - 7a² - 34ab + 5b²
= 9a² - 18ab + 9b² square units