Question

plz answer fast find hcf of polynomial xcube -4x sq+ x+ 6 and (6x sq +x -1)(x - 3)cube

Answer 1

$x - 3$

$x - 145$

Answer 2

Answer:

Given polynomials x³ - 4x² + x + 6 and (6x² + x - 1)(x - 1)³

Factorisation :- x³ - 4x² + x + 6

= x³ + x² - 5x² - 5x + 6x + 6

= x² (x + 1) - 5x(x + 1) + 6(x + 1)

= (x² - 5x + 6)(x + 1)

= (x² - 2x - 3x + 6)(x + 1)

= (x - 2)(x - 3)(x + 1)

Factorisation :- (6x² + x - 1)(x - 1)³

= (6x² + 3x -2x - 1)(x - 1)³

= (2x +1)(3x - 1)(x - 1)³

Common factor = 1

Hence, HCF of given polynomials is 1

Step-by-step explanation: