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Answer:
Given,
AB = PQ
In ∆AOB & ∆POQ
AB = PQ (Given)
OAB = OQP => 90°
AOB = QOP (Vertically Opposite Angles)
So, ∆AOB congruent to ∆POQ by ASA congruence.
By that AQ bisects PB by CPCT.
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