plz answer fast I'll mark as brainlist x²-3√5x+10=0
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==> x² - 3√5x + 10 = 0
On comparing this Quadratic equation with the standard form of Quadratic equation (i.e, ax² + bc + c = 0 ) , we get
a = 1, b = -3√5 , c = 10
Discriminant, D = b² - 4ac
==> D = (-3√5)² - 4*1*10
==> D = 45 - 40
==> D = 5
We know,
x = ( -b ± √D ) / 2a
x = ( -(-3√5) ± √5 ) / 2×1
x = ( 3√5 ± √5 ) / 2
Case-1:
==> x = (3√5 + √5) / 2
==> x = 4√5 / 2
==> x = 2√5
Case-2:
==> x = (3√5 - √5) / 2
==> x = 2√5 / 2
==> x = √5
Hence, Zeroes of the following quadratic equation are 2√5 and √5
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