Question

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Answer 1

Refer to the attachment.



Hope this helps.

Answer 2

Equivalent Resistance in upper part of wire is 10x40/50 = 8 ohm

Equivalent Resistance in lower part of wire is 10 ohm. Calculated by using 1/R= 1/R1 + 1/R2 +1/R3

Now, the Final resistance( in series ) is 8+10 ohm = 18ohm

V=IR ---> I=V/R ---> I= 12/18 Ampere = 2/3 Ampere