Math, asked by american1251, 9 months ago

plz answer fast I require it immediately​

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Answered by aryangupta0504
2

Answer:let a and 1/a be the zeroes

a x 1/a = 8k/ (k^2 + 16)

1 = 8k/ (k^2 + 16)

k^2 + 16 = 8k

k^2 + 16 -8k = 0

(k-4)^2=0

k = 4

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Step-by-step explanation:

Answered by vinayraghav0007
1

Answer:

product of zeroes = c/a

1 = 8k/(k^2+16)

k^2+16 = 8k

k^2 -8k +16 = 0

k^2 -4k-4k +16 =0

k = 4;4

hope it will help you

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